e: \(4\dfrac{25}{16}+25\left(\dfrac{9}{16}:\dfrac{125}{64}:\dfrac{-27}{8}\right)\)
\(=\dfrac{89}{16}+25\cdot\left(\dfrac{9}{16}\cdot\dfrac{64}{125}\cdot\dfrac{-8}{27}\right)\)
\(=\dfrac{89}{16}+25\cdot\left(\dfrac{9}{27}\cdot\dfrac{64}{16}\cdot\dfrac{-8}{125}\right)\)
\(=\dfrac{89}{16}+\dfrac{-8}{5}\cdot3\cdot4\)
\(=\dfrac{89}{16}+\dfrac{-96}{5}=\dfrac{-1091}{80}\)
g: \(\dfrac{2}{3}-4\left(\dfrac{1}{2}+\dfrac{3}{4}\right)\)
\(=\dfrac{2}{3}-4\cdot\dfrac{2+3}{4}\)
\(=\dfrac{2}{3}-5=-\dfrac{13}{3}\)
d: \(\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right)\cdot230\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{7}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
\(=\dfrac{\left(13+\dfrac{1}{4}-2-\dfrac{5}{27}-10-\dfrac{5}{6}\right)\cdot230,04+46,75}{\left(\dfrac{10}{7}+\dfrac{10}{3}\right):\left(12+\dfrac{1}{3}-14-\dfrac{2}{7}\right)}\)
\(=\dfrac{\left(1+\dfrac{1}{4}-\dfrac{5}{27}-\dfrac{5}{6}\right)\cdot230.04+46,75}{\dfrac{100}{21}:\left(-2+\dfrac{1}{3}-\dfrac{2}{7}\right)}\)
\(=\dfrac{\dfrac{25}{108}\cdot230,04+46,75}{\dfrac{100}{21}:\dfrac{-42+7-6}{21}}\)
\(=\dfrac{53,25+46,75}{\dfrac{100}{21}\cdot\dfrac{21}{-41}}\)
\(=100:\dfrac{100}{-41}=-41\)