Question

Answer 1

`# \text {<3 08.}`

`|2x + 4/3| = 2/3`

\(\Rightarrow\left[{}\begin{matrix}2x+\dfrac{4}{3}=\dfrac{2}{3}\\2x+\dfrac{4}{3}=-\dfrac{2}{3}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=\dfrac{2}{3}-\dfrac{4}{3}\\2x=-\dfrac{2}{3}-\dfrac{4}{3}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=-\dfrac{2}{3}\\2x=-2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{3}\\x=-1\end{matrix}\right.\\\text{ Vậy, }x\in\left\{-1;-\dfrac{1}{3}\right\}.\) 

Answer 2

Bạn tham khảo nhé.