Question

Answer 1

`(x-1/3)^2=25/9`

`(x-1/3)^2=(5/3)^2` hoặc `(x-1/3)^2=(-5/3)^2`

`@TH1: x-1/3=5/3=>x=5/3+1/3=6/3=2`

`@TH2: x-1/3=-5/3=>x=-5/3+1/3=-4/3`

Answer 2

`(x-1/3)^2 = 25/9`

`=>` \(\left[{}\begin{matrix}\left(x-\dfrac{1}{3}\right)^2=\left(\dfrac{5}{3}\right)^2\\\left(x-\dfrac{1}{3}\right)^2=\left(-\dfrac{5}{3}\right)^2\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x-\dfrac{1}{3}=\dfrac{5}{3}\\x-\dfrac{1}{3}=-\dfrac{5}{3}\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2\\x=-\dfrac{4}{3}\end{matrix}\right.\)

Answer 3

`(x-1/3)^2 = 25/9`

`(x-1/3)^2 = (+- 5/3)^2`

\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{3}=\dfrac{5}{3}\\x-\dfrac{1}{3}=-\dfrac{5}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}+\dfrac{1}{3}\\x=-\dfrac{5}{3}+\dfrac{1}{3}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{6}{3}=2\\x=-\dfrac{4}{3}\end{matrix}\right.\)