\(a,\dfrac{1}{2}+\dfrac{1}{2}=\dfrac{2}{2}=1\\ b,\dfrac{3}{8}+\dfrac{1}{8}=\dfrac{4}{8}=\dfrac{1}{2}\\ c,\dfrac{7}{9}+\dfrac{5}{9}=\dfrac{12}{9}=\dfrac{4}{3}\\ d,\dfrac{1}{6}+\dfrac{2}{6}=\dfrac{3}{6}=\dfrac{1}{2}\\ e,\dfrac{3}{8}+\dfrac{7}{8}=\dfrac{10}{8}=\dfrac{5}{4}\\ g,\dfrac{2}{5}+\dfrac{3}{5}=\dfrac{5}{5}=1\)