Question

Answer 1

\(\Leftrightarrow\left\{{}\begin{matrix}3x=6\\x-3y=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\3y=2-2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=0\end{matrix}\right.\)

Answer 2

\(\left\{{}\begin{matrix}x-3y=2\\2x+3y=4\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x-3y+2x+3y=2+4\\2x+3y=4\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}3x=6\\2x+3y=4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=\dfrac{2.2-4}{3}=0\end{matrix}\right.\)