Question

Answer 1

\(=\lim\limits_{x\rightarrow1}\dfrac{\left(x^2-2\right)\left(x^2-1\right)}{\left(x-1\right)\left(x^2+x+3\right)}=\lim\limits_{x\rightarrow1}\dfrac{\left(x-1\right)\left(x+1\right)\left(x^2-2\right)}{\left(x-1\right)\left(x^2+x+3\right)}\)

\(=\lim\limits_{x\rightarrow1}\dfrac{\left(x+1\right)\left(x^2-2\right)}{x^2+x+3}=\dfrac{-2}{5}\)

Answer 2