\(\lim\limits_{x\rightarrow2}\dfrac{4x^2-5x-6}{7x^2-4x-20}=\lim\limits_{x\rightarrow2}\dfrac{\left(x-2\right)\left(4x+3\right)}{\left(x-2\right)\left(7x+10\right)}\)
\(=\lim\limits_{x\rightarrow2}\dfrac{4x+3}{7x+10}=\dfrac{4.2+3}{7.2+10}=\dfrac{11}{24}\)