a: \(\dfrac{x-1}{x+1}=\dfrac{1}{x-1}\)
\(\Leftrightarrow x^2-2x+1=x+1\)
\(\Leftrightarrow x\left(x-3\right)=0\)
=>x=0(nhận) hoặc x=3(nhận)
b: \(\dfrac{1}{x-2}+3=\dfrac{3-x}{x-2}\)
\(\Leftrightarrow1+3x-6=3-x\)
=>3x-5=3-x
=>4x=8
hay x=2(loại)
c: \(\dfrac{7x-3}{x-1}=\dfrac{2}{3}\)
=>21x-9=2x-2
=>19x=7
hay x=7/19(nhận)
d: \(\dfrac{3}{2x-16}+\dfrac{3x-20}{x-8}+\dfrac{1}{8}=\dfrac{13x-102}{3x-24}\)
\(\Leftrightarrow\dfrac{3+6x-40}{2\left(x-8\right)}+\dfrac{1}{8}=\dfrac{13x-102}{3\left(x-8\right)}\)
\(\Leftrightarrow\dfrac{6x-37}{2\left(x-8\right)}-\dfrac{13x-102}{3\left(x-8\right)}=\dfrac{-1}{8}\)
\(\Leftrightarrow\dfrac{18x-111-26x+204}{6\left(x-8\right)}=\dfrac{-1}{8}\)
\(\Leftrightarrow\dfrac{-8x+93}{6x-48}=\dfrac{-1}{8}\)
=>-64x+744=-6x+48
=>-58x=-696
hay x=12(nhận)
