Question

Answer 1

y là số nguyên âm lớn nhất

=>y=-1

\(x^2+y\)

\(=\left(-\frac12\right)^2+\left(-1\right)=\frac14-1=-\frac34\)

\(x^3-3x^2+0,25\cdot xy^2-4\)

\(=\left(-\frac12\right)^3-3\cdot\left(-\frac12\right)^2+0,25\cdot\frac{-1}{2}\cdot\left(-1\right)-4\)

\(=-\frac18-3\cdot\frac14+\frac18-4=-\frac34-4=-\frac{19}{4}\)

Ta có: \(A=\frac{x^3-3x^2+0,25\cdot xy^2-4}{x^2+y}\)

\(=\frac{-19}{4}:\frac{-3}{4}=\frac{19}{3}\)