Bài 4:
a: \(\Leftrightarrow7x-7=12x+10\)
=>-5x=17
hay x=-17/5
b: \(\Leftrightarrow\left[{}\begin{matrix}3x-2=2x-3\\3x-2=3-2x\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=1\end{matrix}\right.\)
c: \(\Leftrightarrow x\cdot\dfrac{2}{5}+\dfrac{3}{4}=\dfrac{5}{4}-\dfrac{1}{4}=1\)
\(\Leftrightarrow x\cdot\dfrac{2}{5}=\dfrac{1}{4}\)
hay \(x=\dfrac{1}{4}:\dfrac{2}{5}=\dfrac{1}{4}\cdot\dfrac{5}{2}=\dfrac{5}{8}\)
Đúng 0
Bình luận (0)
