Question

Answer 1

a: \(\Leftrightarrow4m^2+4m+1-4m^2+8m=0\)

hay m=-1/12

Answer 2

\(a,\Leftrightarrow\Delta=\left(2m+1\right)^2-4\left(m^2-2m\right)=0\\ \Leftrightarrow4m^2+4m+1-4m^2+8m=0\\ \Leftrightarrow12m=-1\Leftrightarrow m=-\dfrac{1}{12}\\ b,ĐK:m\ne1\\ \text{PT có }n_0\text{ kép }\Leftrightarrow\Delta'=\left(m-2\right)^2-\left(m+1\right)\left(m-1\right)=0\\ \Leftrightarrow m^2-4m+4-m^2+1=0\\ \Leftrightarrow-4m+5=0\\ \Leftrightarrow m=-\dfrac{5}{4}\left(tm\right)\)