Question

Answer 1

Zn+2HCl->ZnCl2+H2

0,1------------------------0,1 mol

n H2=2,24\22,4=0,1 mol

=>m Zn=0,1.65=6,5g

=>m Cu=10,5-6,5=4g

 

Answer 2

\(a,PTHH:Zn+H_2SO_4\to ZnSO_4+H_2\\ b,n_{H_2}=\dfrac{2,24}{22,4}=0,1(mol)\\ \Rightarrow n_{Zn}=0,1(mol)\\ \Rightarrow m_{Zn}=0,1.65=6,5(g)\\ \Rightarrow m_{\text{rắn dư}}=m_{hh}-m_{Zn}=4(g)\)