\(x=\dfrac{1}{3}+\dfrac{3}{4}\)
\(x=\dfrac{13}{12}\)
\(x=\dfrac{1}{3}+\dfrac{3}{4}\\ \Rightarrow x=\dfrac{4}{12}+\dfrac{9}{12}=\dfrac{13}{14}\)
\(x-\dfrac{3}{4}=\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{1}{3}+\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{13}{12}\)
Vậy \(x=\dfrac{13}{12}\)
x - 3/4 = 1/3
x = 1/3 + 3/4
x= 4/12 + 9/ 12
x= 13/12
x - \(\dfrac{3}{4}\) = \(\dfrac{1}{3}\)
x = \(\dfrac{1}{3}\) + \(\dfrac{3}{4}\)
x = \(\dfrac{13}{12}\)