Question

Answer 1

\(a,=\dfrac{2y}{3\left(x+y\right)^2}\\ b,=\dfrac{2\left(x-y\right)}{\left(x-y\right)^2}=\dfrac{2}{x-y}\\ c,=\dfrac{\left(x+5-3\right)\left(x+5+3\right)}{\left(x+2\right)^2}=\dfrac{\left(x+2\right)\left(x+8\right)}{\left(x+2\right)^2}=\dfrac{x+8}{x+2}\\ d,=\dfrac{x^2+2x+3x+6}{\left(x+3\right)^2}=\dfrac{\left(x+2\right)\left(x+3\right)}{\left(x+3\right)^2}=\dfrac{x+2}{x+3}\)

Answer 2

a) \(=\dfrac{2y}{3\left(x+y\right)^2}\)

b) \(=\dfrac{2\left(x-y\right)}{\left(x-y\right)^2}=\dfrac{2}{x-y}\)

c) \(=\dfrac{\left(x+5-3\right)\left(x+5+3\right)}{\left(x+2\right)^2}=\dfrac{\left(x+2\right)\left(x+8\right)}{\left(x+2\right)^2}=\dfrac{x+8}{x+2}\)

d) \(=\dfrac{\left(x+2\right)\left(x+3\right)}{\left(x+3\right)^2}=\dfrac{x+2}{x+3}\)

Answer 3

bài này mà cx hỏi luôn ạ