a)\(\dfrac{1}{7}-\left(-\dfrac{3}{5}\right)+\dfrac{6}{7}-\left|-\dfrac{1}{5}\right|=\dfrac{1}{7}+\dfrac{3}{5}+\dfrac{6}{7}\dfrac{1}{5}=\left(\dfrac{1}{7}+\dfrac{6}{7}\right)+\left(\dfrac{3}{5}-\dfrac{1}{5}\right)=1+\dfrac{2}{5}=\dfrac{7}{5}\)
b) \(\dfrac{8}{13}.\dfrac{11}{18}+\dfrac{7}{18}.\dfrac{8}{13}-1\dfrac{8}{13}=\dfrac{8}{13}\left(\dfrac{11}{18}+\dfrac{7}{18}\right)-\dfrac{21}{13}=\dfrac{8}{13}.1-\dfrac{21}{13}=\dfrac{8}{13}-\dfrac{21}{13}=\dfrac{-13}{13}=-1\)
Đúng 0
Bình luận (0)
