Câu 3 :
\(n_{SO2}=\dfrac{6,72}{22,4}=0,3\left(mol\right)\)
Pt : \(K_2SO_3+2HCl\rightarrow2KCl+SO_2+H_2O|\)
1 2 2 1 1
0,3 0,3
a) \(n_{K2SO3}=\dfrac{0,3.1}{1}=0,3\left(mol\right)\)
\(m_{K2SO3}=0,3.158=47,4\left(g\right)\)
\(m_{BaCl2}=89-47,4=41,6\left(g\right)\)
0/0K2SO3 = \(\dfrac{47,4.100}{89}=53,26\)0/0
0/0BaCl2 = \(\dfrac{41,6.100}{89}=46,74\)0/0
b) Có : \(m_{BaCl2}=41,6\left(g\right)\)
\(n_{BaCl2}=\dfrac{41,6}{208}=0,2\left(mol\right)\)
Pt : \(BaCl_2+H_2SO_4\rightarrow BaSO_4+2HCl|\)
1 1 1 \(\) 2
0,2 0,2
\(K_2SO_3+H_2SO_4\rightarrow K_2SO_4+SO_2+H_2O|\)
1 1 1 1 1
0,3 0,3
\(n_{H2SO4\left(tổng\right)}=0,2+0,3=0,5\left(mol\right)\)
\(V_{ddH2SO4}=\dfrac{0,5}{5}=0,1\left(l\right)\)
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