\(\dfrac{5}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\)
⇔ \(\dfrac{5}{9}:\dfrac{-3}{22}+\dfrac{5}{9}:\dfrac{-3}{5}\)
⇔ \(\dfrac{-110}{27}+\dfrac{-25}{27}\)
⇔ \(-5\)
\(=\dfrac{5}{9}:\left(\dfrac{2}{22}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{10}{15}\right)=\dfrac{5}{9}:\left(-\dfrac{3}{22}\right)+\dfrac{5}{9}:\left(-\dfrac{9}{15}\right)=-\dfrac{110}{27}+-\dfrac{25}{27}=-5\)tick mik nha
\(\dfrac{5}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\\ =\dfrac{5}{9}:\left(-\dfrac{3}{22}\right)+\dfrac{5}{9}:\left(-\dfrac{3}{5}\right)\\ =\dfrac{5}{9}\cdot\left(-\dfrac{22}{3}-\dfrac{5}{3}\right)\\ =\dfrac{5}{9}\cdot\left(-\dfrac{27}{3}\right)\\ =\dfrac{5}{9}\cdot9=5\)
\(\dfrac{5}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)=\dfrac{5}{9}:\left(\dfrac{2}{22}-\dfrac{5}{22}\right)+\dfrac{5}{9}\left(\dfrac{1}{15}-\dfrac{10}{15}\right)=\dfrac{5}{9}:\dfrac{-3}{22}+\dfrac{5}{9}:\dfrac{-9}{15}=\dfrac{5}{9};\left(\dfrac{-3}{22}+\dfrac{-9}{15}\right)=\dfrac{5}{9}:\dfrac{-81}{110}=\dfrac{-550}{729}\)
Hoctot!
Ta có: \(\dfrac{5}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\)
\(=\dfrac{5}{9}:\dfrac{2-5}{22}+\dfrac{5}{9}:\dfrac{1-10}{15}\)
\(=\dfrac{5}{9}\cdot\dfrac{22}{-3}+\dfrac{5}{9}\cdot\dfrac{15}{-9}\)
\(=\dfrac{5}{9}\left(-\dfrac{22}{3}-\dfrac{15}{9}\right)\)
=-5
