Question

Answer 1

`2.(x-(1)/(2))^{2}-(1)/(8)=0`

`->2(x-(1)/(2))^{2}=(1)/(8)`

`->(x-(1)/(2))^{2}=(1)/(4)`

`->x-(1)/(2)=(1)/(2)` hoặc `x-(1)/(2)=-(1)/(2)`

`->x=1` hoặc `x=0`

Answer 2

Ta có: \(2\left(x-\dfrac{1}{2}\right)^2-\dfrac{1}{8}=0\)

\(\Leftrightarrow2\left(x-\dfrac{1}{2}\right)^2=\dfrac{1}{8}\)

\(\Leftrightarrow\left(x-\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=\dfrac{1}{4}\\x-\dfrac{1}{2}=-\dfrac{1}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=\dfrac{1}{4}\end{matrix}\right.\)