Question

Answer 1

a: Ta có: \(\sqrt{4-\sqrt{7}}+\sqrt{4+\sqrt{7}}+5\sqrt{2}\)

\(=\dfrac{\sqrt{8-2\sqrt{7}}+\sqrt{8+2\sqrt{7}}+10}{\sqrt{2}}\)

\(=\dfrac{\sqrt{7}-1+\sqrt{7}+1+10}{\sqrt{2}}\)

\(=\dfrac{2\sqrt{7}+10}{\sqrt{2}}\)

\(=\sqrt{14}+5\sqrt{2}\)

Answer 2

Answer 3

a) \(\sqrt{4-\sqrt{7}}+\sqrt{4+\sqrt{7}}+5\sqrt{2}\)

 => \(\sqrt{4-2,6}+\sqrt{4+2,6}+7,07\)

 => \(1,18+2,56+7,07\)

 => 10,8