\(\left(2\dfrac{1}{3}+3\dfrac{1}{2}\right)\div\left(4\dfrac{1}{6}-3\dfrac{1}{7}\right)+7\dfrac{1}{2}\)

\(=\left(\dfrac{7}{3}+\dfrac{7}{2}\right)\div\left(\dfrac{25}{6}-\dfrac{22}{7}\right)+\dfrac{15}{2}\)

\(=\dfrac{35}{6}\div\dfrac{43}{42}+\dfrac{15}{2}\)

\(\dfrac{245}{43}+\dfrac{15}{2}=\dfrac{1135}{86}\)