\(\Rightarrow\)(x+3)\(\in\)ƯC(15)=1;3;5;15:-1;-3;-5;-15

Vậy x\(\in\){-2;-4;0;-6;2;-8;12;-18}

7+8=15

282+282=564

\(B=\frac{196+197}{197+198}=\frac{196}{197+198}+\frac{197}{197+198}\)

\(Vì\frac{196}{197}>\frac{196}{197+198}Và\frac{197}{198}>\frac{197}{197+198}\)

Suy ra \(\frac{196}{197}+\frac{197}{198}>\frac{196}{197+198}+\frac{197}{197+198}\)

Suy ra A>B

\(\frac{a}{b}=\frac{c}{d}\Rightarrow ad=bc\)

\(\Rightarrow ad-bd=bc-bd\)

\(\Rightarrow d\left(a-b\right)=b\left(c-d\right)\)

\(\Rightarrow\frac{a-b}{b}=\frac{c-d}{d}\left(đpcm\right)\)

9¹⁰¹ = 9¹⁰⁰ . 9

= 9^2.50 . 9

= (9²)⁵⁰ . 9

= 81⁵⁰ . 9

= (....1) . 9

= (....9)

Vậy 9¹⁰¹ có tận cùng là 9

8399999160

giup minh nha cac ban

40 + 48 = 88