benh HO chu benh j dau bn

ung ho cho mk nha moi nguoi

\(\dfrac{1}{x}+\dfrac{1}{x+6}=\dfrac{1}{4}\)

\(\Leftrightarrow\dfrac{4\left(x+6\right)}{4x\left(x=6\right)}+\dfrac{4x}{4x\left(x+6\right)}=\dfrac{x\left(x+6\right)}{4x\left(x+6\right)}\)

\(\Leftrightarrow4\left(x+6\right)+4x=x\left(x+6\right)\)

⇔ -x² - 2x + 24 = 0

=> Δ =(-2)² -4 . (-1). 24

= 100

=> x₁= 4

x₂ = -6

tìm x sao lại z=......??????/