tìm min, max \(y=\sin^2x-4\sin x+3\)

Tìm min max \(y=\frac{\cos^2x+\sin x\cos x}{1+\sin^2x}\)

tìm min max y=sin3x trên [-pi/2;2pi/3]

tìm min max \(y=5cos\sqrt{x+\frac{\pi}{4}}\)

tìm min, max y=sin³x*cosx-cos³x*sinx

tìm min, max của y=4sin²x+2cos²x

\(\sin^8x+\cos^8x=\frac{17}{32}\)

\(4\left(\sin^4x+\cos^4x\right)+\sqrt{3}\sin4x=2\)

\(2\cos^2\frac{x}{2}\left(1-\sin x\right)+\cos^2x=0\)

\(\sin x+\cos X=\left(\sqrt{3}-1\right)\cos2x\)