HOC24
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a) Cách 1: \(\frac{3}{4}:\frac{1}{2}:\frac{16}{15}=\frac{3}{2}:\frac{16}{15}=\frac{45}{32}\)
Cách 2: \(\frac{3}{4}:\frac{1}{2}:\frac{16}{15}=\frac{3}{4}:\frac{16}{15}:\frac{1}{2}=\frac{45}{64}:\frac{1}{2}=\frac{45}{32}\)
Cách 3: \(\frac{3}{4}:\frac{1}{2}:\frac{16}{15}=\frac{3}{4}:\left(\frac{1}{2}\times\frac{16}{15}\right)=\frac{3}{4}:\frac{8}{15}=\frac{45}{32}\)
b) Cách 1: \(\frac{5}{6}:\left(\frac{1}{2}\times\frac{3}{4}\right)=\frac{5}{6}:\frac{3}{8}=\frac{20}{9}\)
Cách 2: \(\frac{5}{6}:\left(\frac{1}{2}\times\frac{3}{4}\right)=\frac{5}{6}:\frac{1}{2}:\frac{3}{4}=\frac{5}{3}:\frac{3}{4}=\frac{20}{9}\)
Cách 3: \(\frac{5}{6}:\left(\frac{1}{2}\times\frac{3}{4}\right)=\frac{5}{6}:\frac{3}{4}:\frac{1}{2}=\frac{10}{9}:\frac{1}{2}=\frac{20}{9}\)
? Đề là gì z ạk!
d) M - (x\(^3\)y\(^2\) - x\(^2\)y + xy) = 2x\(^3\)y\(^2\) - \(\dfrac{3}{2}\)xy
=> M = (2x\(^3\)y\(^2\) - \(\dfrac{3}{2}\)xy) + (x\(^3\)y\(^2\) - x\(^2\)y + xy)
M = 2x\(^3\)y\(^2\) - \(\dfrac{3}{2}\)xy + x\(^3\)y\(^2\) - x\(^2\)y + xy
M = (2x\(^3\) y\(^2\) + x\(^3\)y\(^2\)) + (\(\dfrac{-3}{2}\)xy + xy) - x\(^2\)y
M = 3x\(^3\)y\(^2\) - \(\dfrac{1}{2}\)xy - x\(^2\)y