a,=33+(2y)3=(3+2y).(9−6y+4y2)b,=(\(\dfrac{1}{2}\)x)\(^3\)
−13=(\(\dfrac{1}{2}\)x−1).(\(\dfrac{1}{4}\)x2+\(\dfrac{1}{2}x\)+1)c,=−(x3+\(\dfrac{1}{27}\))=−[x3+(\(\dfrac{1}{3}\))\(^3\)
]=−(x+\(\dfrac{1}{3}\)).(x2+\(\dfrac{1}{3}\)x+\(\dfrac{1}{9}\))

\(a^2+2a+4\)

\(=\left(a+2\right)^2\)

\(-x^3+3x^2-3x+1\)

\(=-\left(x^3-3x^2+3x-1\right)\)

\(=-\left(x-1\right)^3\)