a lm 1 câu mấy câu sau tương tự nha

Ta có: \(\left\{{}\begin{matrix}4x-3y=10\left(1\right)\\2x+7y=8\left(2\right)\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}4x-3y=10\left(1\right)\\4x+14y=16\left(2\right)\end{matrix}\right.\)

Lấy \(\left(2\right)-\left(1\right)\Rightarrow\left(4x+14y\right)-\left(4x-3y\right)=6\)

\(\Leftrightarrow17y=6\)

\(\Leftrightarrow y=\dfrac{6}{17}\)

Thay vào (1) tìm x

\(\sqrt{x^2-4x+4}=\sqrt{\left(x-2\right)^2}=\left|x-2\right|\)\(\ge0\forall x\)

\(\left(a+b+c\right)^2-2\left(a+b+c\right)\left(b+c\right)+\left(b+c\right)^2\)

\(=\left[\left(a+b+c\right)-\left(b+c\right)\right]^2\)

\(=a^2\)

\(x\le3\)

\(\Rightarrow pt\le6\)

\(\dfrac{3}{5}=\dfrac{6}{10}< \dfrac{14}{10}\)

\(\dfrac{7}{8}< \dfrac{5}{2}=\dfrac{20}{8}\)

\(\dfrac{15}{7}=\dfrac{120}{56}>\dfrac{8}{64}=\dfrac{1}{8}=\dfrac{7}{56}\)

\(=235\times\left(64+36\right)=235\times100=23500\)

\(=376\times\left(236-136\right)=376\times100=37600\)

\(=459\times\left(99+1\right)=459\times100=45900\)

\(=567\times\left(125-25\right)=567\times100=56700\)

Diện tích là:

\(\dfrac{104:\left(1+3\right)\times3\times\left[104-104:\left(1+3\right)\times3\right]}{2}=1014cm^2\)

Tự nghĩ đi tham khảo suốt vậy