Khi thực hiện phép tính \(\dfrac{8x+16}{x^2+1}:\left(x+2\right)\), ta có kết quả là
\(\dfrac{8}{x^2+1}\).\(\dfrac{8}{\left(x-1\right)\left(x+1\right)}\).\(\dfrac{1}{x^2+1}\).\(\dfrac{1}{\left(x-1\right)\left(x+1\right)}\).Hướng dẫn giải:\(\dfrac{8x+16}{x^2+1}:\left(x+2\right)\)
\(=\dfrac{8\left(x+2\right)}{\left(x^2+1\right).\left(x+2\right)}\)
\(=\dfrac{8}{x^2+1}\).