1/

Tổng A là tổng các số hạng cách đều nhau 4 đơn vị.

Số số hạng: $(101-1):4+1=26$

$A=(101+1)\times 26:2=1326$

2/

$B=(1+2+2^2)+(2^3+2^4+2^5)+(2^6+2^7+2^8)+(2^9+2^{10}+2^{11})$

$=(1+2+2^2)+2^3(1+2+2^2)+2^6(1+2+2^2)+2^9(1+2+2^2)$

$=(1+2+2^2)(1+2^3+2^6+2^9)$

$=7(1+2^3+2^6+2^9)\vdots 7$

3/
$C=1+2+2^2+2^3+...+2^{99}$

$2C=2+2^2+2^3+2^4+...+2^{100}$

$\Rightarrow 2C-C=2^{100}-1$

$\Rightarrow C=2^{100}-1$

giúp minh

a) \(A=1+2+2^2+2^3+...+2^{99}\)

\(\Rightarrow2A=2+2^2+2^3+...+2^{100}\)

\(\Rightarrow A=2A-A=2+2^2+...+2^{100}-1-2-2^2-...-2^{99}=2^{100}-1\)

b) \(A=1+2+2^2+...+2^{99}=\left(1+2+2^2+2^3\right)+2^4\left(1+2+2^2+2^3\right)+...+2^{96}\left(1+2+2^2+2^3\right)\)

\(=15+2^4.15+...+2^{96}.15=15\left(1+2^4+...+2^{96}\right)\)

\(=3.5\left(1+2^4+...2^{96}\right)\) chia hết cho 3 và 5

c) \(A=1+2+2^2+...+2^{99}\)

\(=1+2\left(1+2+2^2\right)+...+2^{97}\left(1+2+2^2\right)\)

\(=1+2.7+...+2^{97}.7=1+7\left(2+...+2^{97}\right)\) chia 7 dư 1

=> A không chia hết cho 7

\(C=\dfrac{\sqrt{y^3}-1}{y+\sqrt{y}+1}-\dfrac{y+3\sqrt{y}+2}{\sqrt{y}+1}\) 

\(C=\dfrac{\sqrt{y^3}-1^3}{y+\sqrt{y}+1}-\dfrac{y+\sqrt{y}+2\sqrt{y}+2}{\sqrt{y}+1}\)

\(C=\dfrac{\left(\sqrt{y}+1\right)\left[\left(\sqrt{y}\right)^2+\sqrt{y}\cdot1+1\right]}{y+\sqrt{y}+1}-\dfrac{\left(\sqrt{y}+1\right)\left(\sqrt{y}+2\right)}{\sqrt{y}+1}\)

\(C=\dfrac{\left(\sqrt{y}+1\right)\left(y+\sqrt{y}+1\right)}{y+\sqrt{y}+1}-\left(\sqrt{y}+2\right)\)

\(C=\sqrt{y}+1-\sqrt{y}-2\)

\(C=-3\)

\(C=\dfrac{\left(\sqrt{y}-1\right)\left(y+\sqrt{y}+1\right)}{y+\sqrt{y}+1}-\dfrac{\left(\sqrt{y}+1\right)\left(\sqrt{y}+2\right)}{\sqrt{y}+1}\)

\(=\sqrt{y}-1-\sqrt{y}-2=-3\)

Ta có:

x³(x+2) – x(x³ + 2³) – 2x(x² – 2²)

= x³ . x + x³ . 2 – (x . x³ + x . 2³) – ( 2x . x² – 2x . 2²)

= x⁴ + 2x³ – (x⁴ + 8x ) – (2x³ – 8x)

= x⁴ + 2x³ – x⁴ – 8x – 2x³ + 8x

= (x⁴ – x⁴) + (2x³ – 2x³) + (-8x + 8x)

= 0

`C=\sqrt{b^2(b-1)^2}`      `(b < 0)`

Vì `b < 0=>b < 1`

`=>C=|b|.|b-1|`

`=>C=-b(1-b)=b^2-b`

_________

`D=\sqrt{[(x-2)^4]/[(3-x)^2]}+[x^2-1]/[x-3]`     `(x < 3=>3-x > 0)`

`D=[(x-2)^2]/[3-x]-[x^2-1]/[3-x]`

`D=[x^2-4x+4-x^2+1]/[3-x]`

`D=[-4x+5]/[3-x]`

\(A=2+2^2+2^3+2^4+...+2^{99}+2^{100}\)

\(\Rightarrow2A=2^2+2^3+2^4+...+2^{100}+2^{101}\)

\(\Rightarrow A=2A-A=2^2+2^3+2^4+...+2^{100}+2^{101}-2-2^2-2^3-2^4-...-2^{99}-2^{100}=2^{101}-2\)

\(\Leftrightarrow2P=2^2+2^3+...+2^{100}\\ \Leftrightarrow2P-P=2^2+2^3+...+2^{100}-2-2^2-...-2^{99}\\ \Leftrightarrow P=2^{100}-2\)