=-17/44:7/11+5/77:7/11

=(-1 7/44+5/77):7/11

=-9/28:7/11

=-99/196

a)

\(\begin{array}{l}{11^7}{.11^3} =11^{7-3}={11^4};\,\,\,\,\,\,\,{11^7}:{11^7} =11^{7-7}=11^0= 1;\\{7^2}{.7^4} = 7^{2+4}= {7^6};\,\,\,\,\,\,\,\,\,\,\,\,\,{7^2}{.7^4}:{7^3} = 7^{2+4-3}= {7^3}.\end{array}\)

b) +) Phép tính đúng là:

\({9^7}:{9^2} = {9^5}\) vì \({9^7}:{9^2}=9^{7-2} = {9^5}\)

+) Các phép tính sai là:

\({2^{11}}:{2^8} = 6 \) vì \({2^{11}}:{2^8} = 2^{11-8} = 2^3\) ;

\({7^{10}}:{7^2} = {7^5}\) vì \({7^{10}}:{7^2} = 7^{10-2} = 7^8\);

\({5^6}:{5^6} = 5\) vì \({5^6}:{5^6}=5^{6-6}=5^0 =1\)

\(M=\left(\frac{3}{5}+\frac{4}{5}\right)+\left(\frac{3}{7}+\frac{4}{7}\right)-\left(\frac{3}{11}+\frac{4}{11}\right)\)

\(=\frac{7}{5}+1-\frac{7}{11}\)

\(\frac{12}{5}-\frac{7}{11}\)

\(=......t\text{ự}t\text{ính}nh\text{á}\)

\(=\frac{3}{5}+\frac{3}{7}-\frac{3}{11}+\frac{4}{5}+\frac{4}{7}-\frac{4}{11}\)

\(=\left(\frac{3}{5}+\frac{4}{5}\right)+\left(\frac{3}{7}+\frac{4}{7}\right)-\left(\frac{3}{11}+\frac{4}{11}\right)\)

\(=\frac{7}{5}+1-\frac{7}{11}\)

\(=\frac{12}{5}-\frac{7}{11}\)

\(=\frac{97}{55}\)

a) \(\dfrac{3}{7}-\dfrac{4}{11}-\dfrac{3}{7}\)

=\(\left(\dfrac{3}{7}-\dfrac{3}{7}\right)-\dfrac{4}{11}\)

\(=-\dfrac{4}{11}\)

b) \(-\dfrac{5}{11}+\dfrac{3}{8}-\dfrac{6}{11}\)

\(=\left(-\dfrac{5}{11}-\dfrac{6}{11}\right)+\dfrac{3}{8}\)

\(=-1+\dfrac{3}{8}=-\dfrac{8}{8}+\dfrac{3}{8}=-\dfrac{5}{8}\)

c) \(\dfrac{3}{4}-\dfrac{1}{3}-\dfrac{11}{4}\)

\(=\left(\dfrac{3}{4}-\dfrac{11}{4}\right)-\dfrac{1}{3}\)

\(=-2-\dfrac{1}{3}=-\dfrac{6}{3}-\dfrac{1}{3}=-\dfrac{7}{3}\)

`a, 3/7 -4/11-3/7`

`=(3/7-3/7)-4/11`

`= 0/7-4/11`

`= -4/11`

__

`b, -5/11 +3/8 -6/11`

`=(-5/11-6/11)+3/8`

`=-11/11 + 3/8`

`= -1+3/8`

`= -8/8+3/8`

`=- 5/8`

__

`c,3/4 -1/3-11/4`

`=(3/4-11/4)-1/3`

`= -8/4-1/3`

`=-2-1/3`

`= -6/3-1/3`

`=-7/3`

a) 3/7 - 4/11 - 3/7

= (3/7 - 3/7) - 4/11

= -4/11

b) -5/11 + 3/8 - 6/11

= (-5/11 -6/11) + 3/8

= -1 + 3/8

= -5/8

c) 3/4 - 1/3 - 11/4

= (3/4 - 11/4) - 1/3

= -2 - 1/3

= -7/3

ai mần tr mình cho tich

A) 3/7 - 4/11 - 3/7

= (3/7 - 3/7) - 4/11

= -4/11

B) -5/11 + 3/8 - 6/11

= (-5/11 -6/11) + 3/8

= -1 + 3/8

= -5/8

C) 3/4 - 1/3 - 11/4

= (3/4 - 11/4) - 1/3

= -2 - 1/3

= -7/3

\(\frac{\frac{3}{5}+\frac{3}{7}+\frac{3}{11}}{\frac{4}{5}+\frac{4}{7}+\frac{4}{11}}\)\(=\frac{3.\left(\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}{4.\left(\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}=\frac{3}{4}\)

Bằng 3/4 nha

a: =-1/3+1/3=0

b: \(=\dfrac{4}{11}\left(-\dfrac{2}{7}-\dfrac{4}{7}-\dfrac{1}{7}\right)=\dfrac{4}{11}\cdot\left(-1\right)=-\dfrac{4}{11}\)

c: \(=10+\dfrac{5}{9}-3-\dfrac{5}{7}-4-\dfrac{5}{9}=3-\dfrac{5}{7}=\dfrac{16}{7}\)

d: \(=\dfrac{1}{3}+\dfrac{7}{4}-\dfrac{7}{4}+\dfrac{4}{5}=\dfrac{1}{3}+\dfrac{4}{5}=\dfrac{5+12}{15}=\dfrac{17}{15}\)

a: =-1/3+1/3=0

b: =10+59−3−57−4−59=3−57=167=10+59−3−57−4−59=3−57=167

d: 

12+3/7-11+3/7 tính bằng cách thuận tiện nhé

1) 5 + (-4) = 1

2) (-8) + 2 = -6

3) 8 + (-2) = 6

4) 11 + (-3) = 8

5) (-11) + 2 = -9

6) (-7) + 3 = -4

7) (-5) + 5 = 0

8) 11 + (-12) = -1

9) (-18) + 20 = 2

10) (15) + (-12) = 3

11) (-17) + 17 = 0

12) 16 + (-2) = 14

13) (30) + (-14) = 16

14) (-19) + 20 = 1

15) (-18) + 15 = -3

16) (10) + (-6) = 4

17) (-28) + 14 = -14

18) 15 + (-30) = -15

19) (15) + (-4) = 11

20) (-21) + 11 = -10

21) 8 + (-22) = -14

22) (-15) + 4 = -11

23) (-3) + 2 = -1

24) 17 + (-14) = 3

25) 17 + (-14) = 3

thế này đọc đc mới đỉnh

\(a,15\dfrac{3}{13}-\left(3\dfrac{4}{7}+8\dfrac{3}{13}\right)=15\dfrac{3}{13}-3\dfrac{4}{7}-8\dfrac{3}{13}=\left(15\dfrac{3}{13}-8\dfrac{3}{13}\right)-\dfrac{25}{7}=7-\dfrac{25}{7}=\dfrac{49}{7}-\dfrac{25}{7}=\dfrac{24}{7}\)

\(b,\left(7\dfrac{4}{9}+4\dfrac{7}{11}\right)-3\dfrac{4}{9}=\left(7\dfrac{4}{9}-3\dfrac{4}{9}\right)+4\dfrac{4}{9}=4+\dfrac{40}{9}=\dfrac{36}{9}+\dfrac{40}{9}=\dfrac{76}{9}\)

\(c,\dfrac{-7}{9}.\dfrac{4}{11}+\dfrac{-7}{9}.\dfrac{7}{11}+5\dfrac{7}{9}=\dfrac{-7}{9}\left(\dfrac{4}{11}+\dfrac{7}{11}\right)+\dfrac{52}{9}=\dfrac{-7}{9}.1+\dfrac{52}{9}=\dfrac{-7}{9}+\dfrac{52}{9}=\dfrac{45}{9}=5\)

\(d,50\%.1\dfrac{1}{3}.10.\dfrac{7}{35}.0,75=\dfrac{1}{2}.\dfrac{4}{3}.10.\dfrac{1}{5}.\dfrac{3}{4}=\left(\dfrac{1}{2}.\dfrac{1}{5}.10\right).\left(\dfrac{4}{3}.\dfrac{3}{4}\right)=1.1=1\)

\(e,\dfrac{3}{1.4}+\dfrac{3}{4.7}+...+\dfrac{3}{40.43}=1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{40}-\dfrac{1}{43}=1-\dfrac{1}{43}=\dfrac{42}{43}\)