\(lim_{x\rightarrow2}\frac{\left(\sqrt{x^2+6}-2x\right)\left(\sqrt{4x+1}+x\sqrt[3]{x-1}-x^2-1\right)}{x^2-4x+4}\)

cao nhân nào đó giúp với , xin cảm ơn nhiều !

\(lim_{x\rightarrow2^-}\left(\dfrac{1}{x-2}-\dfrac{1}{x^2-4}\right)\)

\(lim_{x\rightarrow2^-}\frac{\left|x-2\right|}{x-2}\)

\(lim_{x->a}\left[\dfrac{1}{\left(x-a\right)^2}\left(x^2-8x+10+\dfrac{81}{x+2\sqrt{x-1}}-2\sqrt{x-1}\right)\right]=\dfrac{21}{16}\)

\(lim_{x->b}\left[\dfrac{4}{\left(x-b\right)^2}\left(x^2-x+2-2\sqrt{x}\right)\right]=c\)

với a,b,c là các số thực. Tìm a,b,c

\(lim_{x\rightarrow2}\dfrac{3x-5}{\left(x-2\right)^2}\)

\(lim_{x->1}\frac{\sqrt[3]{6x-5}-\sqrt{4x-3}}{\left(x-1\right)^2}\)

l\(lim_{x->0}\left(1-x\right)tan\frac{\pi x}{2}\)

Tính giới hạn

a, \(Lim_{n->+\infty}\frac{1+sin\left(n\right)+2^{n+2}}{2-2n+2^n}\)

b,\(Lim_{x->0}\frac{e^x-1-xcos\left(x\right)}{x\left(e^{2x}-1\right)}\)

c,\(Lim_{n->+\infty}\sqrt[2n]{8^n+9^n}\)

d,\(Lim_{x->0}\frac{\ln\left(1+x\right)-xe^3}{x\tan\left(2x\right)}\)

Tính giới hạn

a, \(Lim_{n->+\infty}\frac{1+sin\left(n\right)+2^{n+2}}{2-2n+2^n}\)

b,\(Lim_{x->0}\frac{e^x-1-xcos\left(x\right)}{x\left(e^{2x}-1\right)}\)

c,\(Lim_{n->+\infty}\sqrt[2n]{8^n+9^n}\)

d,\(Lim_{x->0}\frac{\ln\left(1+x\right)-xe^3}{x\tan\left(2x\right)}\)

\(\lim\limits_{x\rightarrow2^-}\dfrac{x^2-4}{\sqrt{\left(x^4+1\right)\left(2-x\right)}}\)