b: \(\Leftrightarrow x^4-4x^2+2x^2-8=0\)

\(\Leftrightarrow x+2=0\)

hay x=-2

C

\(x^2+3x-4x-12=x^2-x-12\)

Chọn C

\(a,\left(x-8\right)\left(x^3+8\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-8=0\\x^3+8=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x^3=-8\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x=-2\end{matrix}\right.\)

\(b,\left(4x-3\right)-\left(x+5\right)=3\left(10-x\right)\\ \Leftrightarrow4x-3-x-5=30-3x\\ \Leftrightarrow3x-8-30+3x=0\\ \Leftrightarrow6x-38=0\\ \Leftrightarrow x=\dfrac{19}{3}\)

TK

`a.(x-8)(x+8)=0`

`⇔³{x−8=0x³+8=2 `

`⇔³³{x=8x³=−2³ `

`⇔{x=8x=−2`

Vậy ` x = 8;-2`

`b. ( 4 x − 3 ) − ( x + 5 ) = 3 . ( 10 − x )`

`⇔ 4 x − 3 − x − 5 = 30 − 3 x`

`⇔ 3 x − 8 = 30 − 3 x`

`⇔ 3 x + 3 x = 30 + 8`

`⇔ 6 x = 38`

`⇔ x = 19/ 3`

Vậy ` x = 19/ 3`

\(a.\left(x-8\right)\left(x^3+8\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-8=0\\x^3+8=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=8\\\left(x+2\right)\left(x^2-2x+4\right)=0\end{matrix}\right.\)

Ta có: \(x^2-2x+4=x^2-2x+1+3=\left(x-1\right)^2+3\ge3>0\)
\(\Rightarrow x=-2\)

Vậy \(S=\left\{-2;8\right\}\)

b.\(\left(4x-3\right)-\left(x+5\right)=3\left(10-x\right)\)

\(\Leftrightarrow4x-3-x-5=30-3x\)

\(\Leftrightarrow6x=38\)

\(\Leftrightarrow x=\dfrac{19}{3}\)

Vậy \(S=\left\{\dfrac{19}{3}\right\}\)

b: \(\Leftrightarrow x-15-27-x+x-13=-1\)

\(\Leftrightarrow x-55=-1\)

hay x=54

a) x−(−15)=−13−(−85−13)

=> x+15=85

=>x=70

b) (−9−x)+(x−14)=17−(−8+x)

=>-9-x+x-14=17+8-x

=>-23=25-x

=>x=48

a, x=70

b,x=48

kick nha

a) x−(−15)=−13−(−85−13)

=> x+15=85

=>x=70

b) (−9−x)+(x−14)=17−(−8+x)

=>-9-x+x-14=17+8-x

=>-23=25-x

=>x=48

[ chúc bạn học tốt ]

x=-3 ; y=-4 hoặc x=-4; y=-3 

các bạn cho mk vài li-ke cho tròn 760 với 

\(5+x=2^3-1\\ 5+x=8-1\\ 5+x=7\\ x=2\)

bạn ơi lên mạng tìm nha bạn có nhiều lắm

k tui nha

thanks