d) 26 = 2 . 13

38 = 2 . 19

ƯCLN(26,38) = 2

ƯC(26,38) = Ư(2) = 1,2

Mà theo đề bài : 26 ⋮ (x-1) ; 38 ⋮ (x-1)

Nên : x = 2 hoặc 3

\(26⋮\left(x-1\right);38⋮\left(x-1\right)\Rightarrow x-1\inƯC\left(26,38\right)=\left\{\pm2;\pm1\right\}\Rightarrow x\in\left\{-1;0;2;3\right\}\)

Mà x là số tự nhiên \(\Rightarrow x\in\left\{0;2;3\right\}\)

\(\Rightarrow\left(x-1\right)\inƯC\left(26,38\right)=Ư\left(2\right)=\left\{1;2\right\}\\ \Rightarrow x\in\left\{2;3\right\}\)

\(125+\left(24-x\right)=17\)

\(\Rightarrow24-x=17-125\)

\(\Rightarrow24-x=-108\)

\(\Rightarrow-x=-108-24\)

\(\Rightarrow-x=-132\)

\(\Rightarrow x=132\)

\(\Rightarrow24-x=17-125=-108\\ \Rightarrow x=24-\left(-108\right)=24+108=132\)

Mình trình bày trong hình ^^ Bn tham khảo nhé

d: Ta có: \(9x^2+6x-8=0\)

\(\Leftrightarrow9x^2+12x-6x-8=0\)

\(\Leftrightarrow\left(3x+4\right)\left(3x-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{4}{3}\\x=\dfrac{2}{3}\end{matrix}\right.\)

e: Ta có: \(x\left(x-2\right)+x-2=0\)

\(\Leftrightarrow\left(x-2\right)\left(x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)

f: Ta có: \(5x\left(x-3\right)-x+3=0\)

\(\Leftrightarrow\left(x-3\right)\left(5x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{5}\end{matrix}\right.\)

d)2².2^x=16

⇔4.2^x=16

⇔2^x=4

⇔2^x=2²

⇔x=2

2^x=2⁴:2²

2^x=2²

=> x=2

X=2 bạn nhé

\(8x-48+4x-12-14=-x+4\)

\(\Leftrightarrow12x-75=-x+4\Leftrightarrow13x=79\Leftrightarrow x=\dfrac{79}{13}\)

\(-7\left(8-x\right)-6\left(x+9\right)=20-x\Leftrightarrow-56+7x-6x-54=20-x\)

\(\Leftrightarrow2x=130\Leftrightarrow x=65\)

\(9x-63-80+60x=-7x+15\Leftrightarrow76x=158\Leftrightarrow x=\dfrac{79}{38}\)

\(-96-16x-60+30x=-40x-16\Leftrightarrow54x=140\Leftrightarrow x=\dfrac{70}{27}\)

\(17x-102-14x-28=4x-24-2x+4\Leftrightarrow x=110\)

a: x-4/5=3/7

=>x=3/7+4/5=43/35

b: x+3/7=4/5

=>x=4/5-3/7=13/35

c: 19/20-x=8/5-3/4

=>19/20-x=32/20-15/20=17/20

=>x=2/20=1/10

d: =>4/5*x=2/21

=>x=2/21:4/5=5/42

e: =>x:7/9=6/8

=>x=6/8*7/9=3/4*7/9=21/36=7/12

f: =>x/6=2/3-1/3=1/3

=>x=2

a: x-4/5=3/7

=>x=3/7+4/5=43/35

b: x+3/7=4/5

=>x=4/5-3/7=13/35

c: 19/20-x=8/5-3/4

=>19/20-x=32/20-15/20=17/20

=>x=2/20=1/10

d: =>4/5*x=11/21

=>x=55/84

e: =>x=6/8*7/9=42/72=7/12

f: =>x/6=2/3-1/3=1/3

=>x=2

Phương pháp giải:

- Muốn tìm một số hạng ta lấy tổng trừ đi số hạng kia.

- Muốn tìm một thừa số ta lấy tích chia cho thừa số kia. 

Lời giải chi tiết:

a)

● x + 3 = 6

    x = 6 − 3

    x = 3

● x × 3 = 6

    x = 6 : 3

    x = 2

b)

● 4 + x = 12

    x = 12 − 4

    x = 8

● 4 × x = 12

    x = 12 : 4

    x = 3

a) \(M(x) = A(x) + B(x) \\= 4{x^4} + 6{x^2} - 7{x^3} - 5x - 6 - 5{x^2} + 7{x^3} + 5x + 4 - 4{x^4} \\=(4x^4-4x^4)+(-7x^3+7x^3)+(6x^2-5x^2)+(-5x+5x)+(-6+4)\\= {x^2} - 2.\)

b) \(A(x) = B(x) + C(x) \Rightarrow C(x) = A(x) - B(x)\)

\(\begin{array}{l}C(x) = A(x) - B(x)\\ = 4{x^4} + 6{x^2} - 7{x^3} - 5x - 6 - ( - 5{x^2} + 7{x^3} + 5x + 4 - 4{x^4})\\ = 4{x^4} + 6{x^2} - 7{x^3} - 5x - 6 + 5{x^2} - 7{x^3} - 5x - 4 + 4{x^4}\\ =(4x^4+4x^4)+(-7x^3-7x^3)+(6x^2+5x^2)+(-5x-5x)+(-6-4)\\= 8{x^4} - 14{x^3} + 11{x^2} - 10x - 10\end{array}\)