Khi thực hiện phép chia phân thức \(\dfrac{5x+15}{\left(x-2\right)^2}:\dfrac{x+3}{x^2-4}\), ta có kết quả là
\(\dfrac{5\left(x+2\right)}{x-2}\).\(\dfrac{-5\left(x+2\right)}{x-2}\).\(5\left(x-2\right)\).\(5\left(x+2\right)\).Hướng dẫn giải:\(\dfrac{5x+15}{\left(x-2\right)^2}:\dfrac{x+3}{x^2-4}\)
\(=\dfrac{5\left(x+3\right)}{\left(x-2\right)^2}.\dfrac{\left(x-2\right)\left(x+2\right)}{x+3}\)
\(=\dfrac{5\left(x+2\right)}{x-2}\).