Question

Hoàn thành sơ đồ:

Tinh bột\(\underrightarrow{\left(1\right)}C_6H_{12}O_6\underrightarrow{\left(2\right)}C_2H_5OH\underrightarrow{\left(3\right)}CO_2\underrightarrow{\left(4\right)}Na_2CO_3\underrightarrow{\left(5\right)}CH_3COONa\)

\(C_2H_5OH\underrightarrow{\left(6\right)}H_2\)

\(C_2H_5OH\underrightarrow{\left(7\right)}CH_3COOC_2H_5\)

Answer 1

1)(-C6H10O5-)n +nH2O -axit ;t^o-> nC6H12O6

2) C6H12O6 --men ; 30^o-32^oC--> 2C2H5OH + 2CO2

3) C2H5OH + 3O2 -t^o-> 2CO2 + 3H2O

4) CO2 + 2NaOH -> Na2CO3 + H2O

5) Na2CO3 + 2CH3COOH -> 2CH3COONa + H2O + CO2

6) 2C2H5OH + 2Na -> 2C2H5ONa + H2

7) C2H5OH + CH3COOH -> H2O + CH3COOC2H5

(đk: H2SO4 đ ; t^o)

Answer 2

(1) (C₆H₁₀O₅)_n + nH2O => nC₆H₁₂O₆

(2) C₆H₁₂O₆ => (men rượu, t^o) 2CO₂ + 2C₂H₅OH

(3) C2H5OH + 3O2 => (t^o) 2CO2 + 3H2O

(4) CO2 + 2NaOH => Na2CO3 + H2O

(5) Na2CO3 + 2CH3COOH => 2CH3COONa + CO2 + H2O

(6) C2H5OH + Na => C2H5ONa + 1/2 H2

(7) C2H5OH + CH3COOH => (t^o,xt: H2SO4đ) <pứ hai chiều> CH3COOC2H5 + H2O