ta có : \(\dfrac{x+1}{6}-\dfrac{x+m}{4}>\dfrac{mx-1}{3}\)
\(\Leftrightarrow2x+2-3x-3m>4mx-4\)
\(\Leftrightarrow-\left(4m+1\right)x>3m-6\Leftrightarrow x< \dfrac{6-3m}{4m+1}\)
\(\Rightarrow\) để bất phương trình này có nghiệm \(\Leftrightarrow4m+1\ne0\Leftrightarrow m\ne\dfrac{-1}{4}\)
vậy ..................................
a\(8\left(x+\dfrac{1}{x}\right)^{2^{ }}+4\left(x^{2^{ }}+\dfrac{1}{x^2}\right)-4\left(x^2+\dfrac{1}{x^2}\right)\left(x+\dfrac{1}{x}\right)=\left(x+4\right)^2\)giải các phương trình\(\dfrac{x+4}{2x^2-5x+2}+\dfrac{x+1}{2x^2-7x+3}=\dfrac{2x+5}{2x^2-7x+3}\)
Giải bất phương trình :
a)\(\left|1-x\right|+\left|2x-1\right|>5\)
b)\(\dfrac{2x+\dfrac{3x-4}{5}}{15}< \dfrac{\dfrac{3-x}{2}+7x}{5}+1-x\)
Tìm x
\(\dfrac{4}{5}x^2\left(\dfrac{x}{3}-\dfrac{1}{2}\right)-\left(\dfrac{1}{5}x-\dfrac{2}{3}\right)\left(\dfrac{4x^2}{3}+1\right)=\dfrac{22}{45}x^2\)
MÌNH CẦN GẤP GIÚP MÌNH NHA
Giải phương trình:
a)\(\dfrac{1}{x+1}-\dfrac{5}{x-2}=\dfrac{15}{\left(x+1\right)\left(2-x\right)}\)
b) \(1+\dfrac{x}{3-x}=\dfrac{5x}{\left(x+2\right)\left(3-x\right)}+\dfrac{2}{x+2}\)
c)\(\dfrac{6}{x-1}-\dfrac{4}{x-3}=\dfrac{8}{\left(x-1\right)\left(3-x\right)}\)
d) \(\dfrac{x+2}{x-2}-\dfrac{1}{x}=\dfrac{2}{x\left(x-2\right)}\)
Tìm x
\(\dfrac{4}{5}x^2\left(\dfrac{x}{3}-\dfrac{1}{2}\right)-\left(\dfrac{1}{5}x-\dfrac{2}{3}\right)\left(\dfrac{4x^2}{3}+1\right)=\dfrac{22}{45}x^2\)
giải phương trình :
a) \(\dfrac{x+2}{x+1}+\dfrac{3}{x-2}=\dfrac{3}{x^2-x-2}+1\)
b)\(\dfrac{x+6}{x-5}+\dfrac{x-5}{x+6}=\dfrac{2x^2+23x+61}{x^2+x-30}\)
giải phương trình :
\(\dfrac{x-5}{x-5}+\dfrac{x-6}{x-5}+\dfrac{x-7}{x-5}...\dfrac{1}{x-5}=4\)
(xϵN)
\(B=4\dfrac{1}{113}x\dfrac{1}{371}-\dfrac{2}{113}x5\dfrac{370}{371}-\dfrac{3}{113x117}-\dfrac{4}{371}\)
Giúp mình với@@!
Tìm các giá trị của x để giá trị các biểu thức sau bằng 0 :
a, \(\dfrac{x^2-x}{x^2+x+1}\)
b, \(\dfrac{x+1}{x\left(x+2\right)}\)
c, \(\dfrac{x^2-1}{x^2+3}\)
d, \(\dfrac{98x^2-2}{x-2}\)
e, \(\dfrac{3x-2}{x^2+2x+1}\)
f, \(\dfrac{x}{x^2-4}\)- \(\dfrac{3-x}{\left(x+2\right)^2}\)
