Question

X/y=3/2;y/2=5/7 va |2x-3y+5z|=1

Answer 1

ta có:\(\dfrac{y}{2}=\dfrac{3}{7}\)

=>\(y=\dfrac{2.3}{7}=\dfrac{6}{7}\)

ta có:\(\dfrac{x}{y}=\dfrac{3}{2}=>\dfrac{x}{\dfrac{6}{7}}=\dfrac{3}{2}=>x=\dfrac{\dfrac{6}{7}.3}{2}=\dfrac{9}{7}\)

ta có:\(\)/2x-3y+5z/=1

=>/\(\dfrac{2.9}{7}-\dfrac{3.6}{7}+5z\)/=1

<=>/\(\dfrac{18}{7}-\dfrac{18}{7}+5z\)/=1

<=>/\(5x\)/=1

<=>5x=1 hoặc 5x=-1

<=>x=\(\dfrac{1}{5}=0,2\) hoặc x=\(-\dfrac{1}{5}=-0,2\)

vậy: x= \(\dfrac{9}{7}\) ; y=\(\dfrac{6}{7}\) ; z=0,2 và -0,2