Question

X^4-1/(x^2-1)(x+2)

Answer 1

\(=\dfrac{\left(x^2-1\right)\left(x^2+1\right)}{\left(x^2-1\right)\left(x+2\right)}=\dfrac{x^2+1}{x+2}\)

Answer 2

\(\dfrac{x^4-1}{\left(x^2-1\right)\left(x+2\right)}\\ =\dfrac{\left(x^2-1\right)\left(x^2+1\right)}{\left(x-1\right)\left(x+1\right)\left(x+2\right)}\\ =\dfrac{\left(x-1\right)\left(x+1\right)\left(x^2+1\right)}{\left(x-1\right)\left(x+1\right)\left(x+2\right)}\\ =\dfrac{x^2+1}{x+2}\)