\(x+30\%x=-1,31\\ x+\dfrac{3}{10}x=-1\dfrac{31}{100}\\ x\cdot\left(1+\dfrac{3}{10}\right)=-\dfrac{131}{100}\\ x\cdot\dfrac{13}{10}=-\dfrac{131}{100}\\ x=-\dfrac{131}{100}:\dfrac{13}{10}=\dfrac{-131}{100}\cdot\dfrac{10}{13}=-\dfrac{131}{130}\)
Tị̀m X
101x=(x16)x
(30+4.x)40=(30.x)40
(7500:9+x)=x302
(100:x)x=7.9x
Tìm x∈Z, biết:
-(38-x)-(37-x)=30-x
(x+1) + (x+2) + (x+3) + ... + (x+30) = 756
x-1/12 x-1/20 x-1/30 x-1/42 x-1/56 x-1/72=224
30%x+x=52
12 x 56 x 2 + 6 x 14 x 4 + 3 x 30 x 8
tìm x biết : 4^30=16^x
Tìm x
x : 40=43+x
M:C=4x
x30=(1030x)40
101x=(x16)x
(30+4.x)40=(30.x)40
(7500:9+x)101=(x)302
(100:x)x=7.9x
C={972 ϵ N , 2 = hoac <x<hoac = 10}
101302=0x
tìm x, biết
x –30%.x= -6/5
