x2 - x = 0
<=> x(x-1) = 0
<=> \(\left[\begin{array}{nghiempt}x=0\\x-1=0\end{array}\right.\)
<=> \(\left[\begin{array}{nghiempt}x=0\\x=1\end{array}\right.\)
Ta có:\(x^2\)-x=0
\(\Leftrightarrow\)x.x-x=0
\(\Leftrightarrow\)x.(x-1)=0
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x-1=0\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x=1\end{array}\right.\)
Vậy x=0 hoặc x=1