\(x^2-4=5\\ \Rightarrow x^2=9\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
Vậy \(x\in\left\{3;-3\right\}\)
Ta có: \(x^2-4=5\)
\(\Leftrightarrow x^2=9\)
hay \(x\in\left\{3;-3\right\}\)
Vậy: \(x\in\left\{3;-3\right\}\)
x^2 -4=5
<=> x^2= 5-4
<=> x^2=1=1^2
=>x=1
mũ hai mk k vt đc nên vt ^2 nha