\(x^{15}=x\\ x^{15}-x=0\\ x\left(x^{14}-1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x^{14}=1\Rightarrow\left[{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\end{matrix}\right.\)
vậy ......
\(x^{15}=x\)
\(\Rightarrow x^{15}-x=0\)
\(x\left(x^{14}-1\right)=0\)
\(x=0\)
\(x^{14}-1=0\Rightarrow x^{14}=1\Rightarrow x=\pm1\)