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tìm x :a)(2x-3/4)^2=(3-x)^2
b)(5/3x-1/3)^5=(2x+3/4)^3
HELP ME !!!!!!!!!!!!!!!!!!!
a) 2/3 + 1/3 : x= 3/5
b) ( 2x/3 - 3 ) : (-10) = 2/5
c) | 2x + 1 | = 4
d) | 2x - 1 | +1 = 4
e ) 8 - | 1 - 3x | = 1/81
f) 1,5 x - 7/3 * x = 1,5 - 2/3
g) (1/2)^2x-1 = 1/8
h) ( -1/3 )^x-3 = 1/81
Bài 1 : Tìm x
a) 2x + 1 phần 7 = 1 phần 3
b) 3(x - 1 phần 2) = 4 phần 9
c) ( x - 5)2 + 4 = 68
d) (|x|- 1 phần 2 ) (2x + 3 phần 2) = 0
e) 5x + 2 = 3x + 8
f) 26 - (5 - 2x) = 27
g) ( 4x - 8 ) - ( 2x - 6 ) = 4
h) (x + 3)3 ÷ 3 - 1 = - 10
a,(x-4)(2x-3)>0
b,(x-1)(2x+5)<0
c,(2x-3)(4-5x)=0
Các bn giúp mk vs nha!!!
tim x
a, ( 3-2x ) . ( 1/3 - 1/2 ) ^2 + 4 . (7-5x ) = 9-2x
b, 7 - 3x 1 - 3x
_______ = ______
4 + x x - 5
Tìm số nguyên
-x/2+2x/3+x+1/4+2x+1/6=8/3
1) 4x-(2x-5)=21
2) 14x+5=8x+10
3) 15+5x=3x+30
4) 2x-5=15-3x
5) 2(3x+5)+3(x+1)=6x+20
6) 4(x-3)+5(x-3)=18
Bài 13: Tìm x:
1/ (2x – 15) + 17 = 6
2/ 15 – (4 – 3x) = - 4
3/ - 21 + 3(-x + 7) = -18
4/ 78 : (3x – 2) = -3
5/ -35 : 5.(-3 – 2x) = 35
\(\frac{12}{16}=\frac{-x}{4}=\frac{21}{y}=\frac{z}{80}\) \((-0,6x-\frac{1}{2}).\frac{3}{4}-\left(-1\right)=\frac{1}{3}\)
\(\frac{1}{3}x+\frac{2}{5}\left(x-1\right)=0\)
\(\left(2x-3\right).\left(6-2x\right)=0\)
\(\frac{-2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)
\(2|\frac{1}{2}x-\frac{1}{3}|-\frac{3}{2}=\frac{1}{4}\)
\(\frac{3}{4}-2|2x-\frac{2}{3}|=2\)