\(\left(x-3\right).\left(2x-7\right)=0\)
\(\Rightarrow\left[\begin{matrix}x-3=0\\2x-7=0\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=3\\x=\frac{7}{2}\end{matrix}\right.\)
Vậy x= 3 hoặc x= \(\frac{7}{2}\)
\(\left(x-3\right)\left(2x-7\right)=0\)
\(\Rightarrow\left[\begin{matrix}x-3=0\\2x-7=0\end{matrix}\right.\)\(\Leftrightarrow\left[\begin{matrix}x=3\\2x=7\end{matrix}\right.\)\(\Leftrightarrow\left[\begin{matrix}x=3\\x\in\varnothing\end{matrix}\right.\)
Vậy x = 3
(x-3).(2x-7)=0
=> x-3=0 Hoặc 2x-7=0
=>x=3 x=7/2
Vậy x=3;x=7/2