Đề bài : Rút gọn
Ta có : ( x -2 ) . ( x + \(\dfrac{2}{3}\) )
= x2 + \(\dfrac{2}{3}x\) - 2x + \(\dfrac{-4}{3}\)
= x2+ x.(\(\dfrac{2}{3}-2\) ) + \(\dfrac{-4}{3}\)
= x2 + \(\dfrac{-4}{3}x\) + \(\dfrac{-4}{3}\)
= x2 + x . ( 1 + x )
\(\left(x-2\right)\left(x+\dfrac{2}{3}\right)\)
\(=x\left(x+\dfrac{2}{3}\right)-2\left(x+\dfrac{2}{3}\right)\)
\(=x^2+\dfrac{2}{3}x-2x-\dfrac{4}{3}\)
\(=x^2+\dfrac{-4}{3}x-\dfrac{4}{3}\)