a: =>x-25+12-2x=-13
=>-13-x=-13
=>x=0
b: =>-2x-15-12+x=2
=>-x-27=2
=>-x=29
hay x=-29
c: =>4x-5+3x-8x+12=45
=>-x+7=45
=>-x=38
hay x=-38
\(\left(x-1\right)⋮\left(x+5\right)\)
\(\left(4x-3\right)⋮\left(2x-1\right)\)
\(\left|4x+12\right|+\left|18-3y\right|=0\)
1: \(15-\left\{2\cdot\left[x-\left(2x-4\right)\cdot5\right]\cdot3\cdot\left(x+1\right)\right\}=12-x\)
Tìm x thuộc Z, biết:
a. 1 + \(\left\{-2-[-3+\left(-4+\left|x\right|\right)]\right\}=1-2+[\left(-3-4\right)]\)
b. 34 + (9 - 21) = 3417 - (x + 3417)
c. x - \(\left\{55-[49+\left(-28-x\right)]\right\}=13-\left\{47+[25-\left(32-x\right)]\right\}\)
d. (15 - x) + (x - 12) = 7 - (-8 + x)
e. - 7 + \(\left|x-4\right|\) = - 3
f. 13 - \(|\)x + 5\(|\) = 13
g. \(|\)x + 1\(|\) > 2
h. \(|\)x + 2\(|\) ≤ 5
i. \(|\)x - 10\(|\) - (-12) = 4
Tìm x :
a) \(\left|x+\dfrac{11}{17}\right|+\left|x+\dfrac{2}{17}\right|+\left|x+\dfrac{4}{17}\right|=4x\)
b) \(\left|x+\dfrac{1}{2}\right|+\left|x+\dfrac{1}{6}\right|+\left|x+\dfrac{1}{12}\right|+\left|x+\dfrac{1}{20}\right|+..+\left|x+\dfrac{1}{110}\right|=11x\)
1: \(\left(x-2\right)^2-2\cdot\left(x+1\right)^2=\left(2x+1\right)\cdot\left(1-3x\right)-2x\cdot\left(1-x\right)\)
\(a,1\frac{13}{15}.0,75-\left(\frac{8}{15}+0,25\right).\frac{24}{47}\)
\(b,5:\left(4\frac{3}{4}-1\frac{25}{28}\right)-1\frac{3}{8}:\left(\frac{3}{8}+\frac{9}{20}\right)\)
\(c,6\frac{5}{12}:2\frac{3}{4}+11\frac{1}{4}.\left(\frac{1}{3}-\frac{1}{5}\right)\)
\(d,\left(\frac{3}{5}+0,415-\frac{3}{200}\right).2\frac{2}{3}.0,25\)
\(e,\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(g,1\frac{13}{15}.0,75-\left(\frac{11}{20}+25\%\right);\frac{7}{3}\)
\(\left(x+2\right)+\left(x+12\right)\left(x+42\right)+\left(x+47\right)=655\)
\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+2009\right)=2009\cdot2010\)
TÌM X
\(7-\left\{12-\left[-\left(-3\right)+\left(-10\right)-\left(-11\right)\right]-\left[-\left(-9\right)+\left(-8\right)-\left(+12\right)\right]\right\}-\left(-4\right)\)
1. Có 24 gói đường gồm 3 loại. gói 5 lạng, gói 2 lạng, gói 1 lạng có khối lượng tổng cộng là 45 lạng. số gói 1 lạng gấp 3 lần số gói 2 lạng. tính số gói mỗi loại?
2, tim x
\(3x-\left\{2\left[x-3\left(x+1\right)+3\cdot\left(1-2x\right)\right]-2\cdot\left(x+1\right)\right\}=1-2x\)
