\(\left(x-2\right)^2\left(x-9\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(x-2\right)^2=0\\x-9=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x-9=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=9\end{matrix}\right.\)
Giúp với mn ơi ;-;a) 9(2x+1)^2-4(x+1)^2=0b) (x+1)^2+2(x+1)+1=0c) (x-1)(x^2-9)+x+3=0d) (7-x)^2__________ -(x+5)^2=0 4e) 4x^2+(x-1)^2-(2x+1)^2=0f) x^3+1=(x+1)(2-x)
(x+2)3-9(x+2)=0
a)(x-1)(x^2+5x-2)-x^3+1=0
b)5(x^2+3x)-9(3x+3)=x^2-36
A.(X+16/49) +(x+18/47)=(x+20/45)-1
B.(x-3/x-2)+(x-2/x-4)=-1
C.(4x-10).(x+6)=0
D.7x-1/2=5+(9-5x/6)
E.3.(7x-1)=30+9-5
F.(3x-9/x+1)-2=4x/x+1
1. giải phương trình tích:
a) \(\left(x+3\right)\left(x^2+2021\right)=0\)
\(\)2. giải các phương trình sau bằng cách đưa về phương trình tích:
b) \(x\left(x-3\right)+3\left(x-3\right)=0\)
c) \(\left(x^2-9\right)+\left(x+3\right)\left(3-2x\right)=0\)
d) \(3x^2+3x=0\)
e) \(x^2-4x+4=4\)
A) (3x+2)(x^2+1)=(9x^2-4)(x+1)
B) x(2x-9)=3x(x-5)
C) (x-3/4)^2+(x-3/4)(x-1/2)=0
giai pt sau:
1/ (2x+7)2=9(x+2)2
2/ (x+2)2=9(x2-4x+4)
3/ (9x2-4). (x+1)=(3x+2).(x2-1)
4/ (x2+x)2+4(x2+x)-12=0
1) Giải các pt tích
a) \(2x^2+7x-9=0\)
b) \(x^2-4x+3=0\)
c) \(x^4+x^3+x+1=0\)
d) \(x^4-x^2+2x+2=0\)
5/ (x2 – 4) + (x – 2)(4 – 2x) = 0
6/ x(2x – 7) – 4x + 14 = 0 7/ x2 – x – (3x – 3) = 0
8/ (x2 – 2x + 1) – 4 = 0 9/ 4x2 + 4x + 1 = x2
10/ x2 – x = - 2x + 2 11/ x2 – 5x + 6 = 0
11/ x^2 -- 5x + 6 = 0
Câu 11 là x mũ 2 nha giúp dùm e nha anh chị .
