Vì : ( x - 1 ) ( x - 2 ) = 0
\(\Rightarrow\left[\begin{matrix}x-1=0\\x-2=0\end{matrix}\right.\)\(\Leftrightarrow\left[\begin{matrix}x=0+1=1\\x=0+2=2\end{matrix}\right.\)
Vậy x = 1 hoặc x = 2
cause (x-1)(x-2)=0
so one of { x-1;x-2} =0
x-1 =0 => x=1
x-2=0 =>x=2
=> x [= { 1 ; 2 }
Vì (x-1).(x-2) = 0
=> (x - 1) = 0 hoặc (x - 2) = 0
Ta có :
+) x - 1 =0 +) x - 2 = 0
x = 0 + 1 x = 0 + 2
x = 1 x = 2
Vậy x \(\in\) {1; 2}