Question

trung hòa 200ml dung dịch hcl 2m thì phải dùng bao nhiêu gam dung dịch CaOH2 lần 10%

Answer 1

2HCl+Ca(OH)2---->CaCl2+2H2O

n HCl=0,2.2=0,4(mol)

Theo pthh

n Ca(OH)2=1/2n HCl=0,2(mol)

m Ca(OH)2=0,2.74=14,8(g)

m dd Ca(OH)2=\(\frac{14,8.100}{10}=148\left(g\right)\)

Answer 2

\(PTHH:Ca\left(OH\right)2+2HCl--->CaCl2+2H2O\)

Ta có :

\(n_{HCl}=0,4\left(mol\right)\)

=>nCa(OH)2 = 1/2 n HCl = 0,02(mol)

=>mCa(OH)2 = 0,2.74=14,8(g)

=>mdd Ca(OH)2 = 148(g)

Answer 3

https://i.imgur.com/fyXP5vN.jpg