PTHH : HCl+NaOH-----> NaCl +H2O
................0,3...0,3(mol)
\(C_{M\left(NaOH\right)}=\frac{0,3}{0,1}=3\left(M\right)\)
#Walker
\(n_{HCl}=2.0,15=0,3\left(mol\right)\\ PTHH:NaOH+HCl\rightarrow NaCl+H_2O\\ C_{M_{NaOH}}=\frac{0,3}{0,1}=3\left(M\right)\)
#Alec
PTHH : NaOH + HCl--->NaCl +H2O
n HCl= 0,15.2 = 0,3 mol
n NaOH= nHCl = 0,3 mol
=> CM NaOH =0,3/ 0,1 = 3M