Question

Trục thức ở mẫu và rút gọn:

\(a.\dfrac{1}{2\sqrt{2}-3\sqrt{3}}\)

\(b.\sqrt{\dfrac{3-\sqrt{5}}{3+\sqrt{5}}}\)

Answer 1

a: \(=\dfrac{2\sqrt{2}+3\sqrt{3}}{8-27}=\dfrac{\left(-2\sqrt{2}-3\sqrt{3}\right)}{19}\)

b: \(=\sqrt{\dfrac{\left(3-\sqrt{5}\right)^2}{4}}=\dfrac{3-\sqrt{5}}{2}\)

Answer 2

`a) 1/(2sqrt(2) - 3sqrt(3)) =(2sqrt(2) +3sqrt(3))/(8-27)=(-2sqrt(2) -3sqrt(3))/19`

`b) sqrt(((3-sqrt(5))/(3+sqrt(5)))^2) = (3-sqrt(5))/2`